Problem: 4x-5(3x+10)=126.
It should be an interger.
I dont know how to do problems with two X's.
I Did:
4x-15x+50=126 126-50=
4x-15x=76 4-15=-11x
76/-11x=6.9 which has to be the wrong way to do it.
Sp can someone please show me how to do it correctly?
It should be an interger.
I dont know how to do problems with two X's.
I Did:
4x-15x+50=126 126-50=
4x-15x=76 4-15=-11x
76/-11x=6.9 which has to be the wrong way to do it.
Sp can someone please show me how to do it correctly?