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I'm having a hard time in my Alg 2 class and I was wondering if someone could please check my homework. Please?
For direct variation, I am using the formula "y = mx". For inverse, I'm using the formula "y = k/x" or "xy = k"
5. The ideal gas law states the volume of a gas V varies, jointly with the number of molecules, M, and the temperature, T, and varies inversely with the pressure, P. If the constant of proportionality is 8.3, which of the following would represent the ideal gas law?
I believe that V varies directly with M and T, so this part of the formula would be:
. . .V = MT
but since it varies inversely with P and the constant is 8.3, I would understand the answer to be
. . .VP/MT=8.3
Could somebody please tell me if this is correct?
Thanks.
7. The surface area of a cylinder varies jointly as the radius and the sum of the radius and the height. A cylinder with height 8 cm and radius 4 cm has a surface area of [96 times pi] cm^2. Find the surface area of a cylinder with radius 3 cm and height 10 cm.
To figure out this problem, I used a proportion. I did
. . .96pi / (4)(12) = Unknown Surface Area / (3)(13)
The 4 is the radius of the first cylinder and the 12 is the sum of the radius and the height.
The 3 is the radius of the second cylinder and the 13 is the sum of the radius and the height.
Then I finished working out the problem and the steps I used are as follows.
. . .(96pi)(3)(13) = (U)(4)(12)
. . .3744pi = 48U
. . .U = 78pi cm^2
So the answer I came up with for this problem was 78pi cm^2
For direct variation, I am using the formula "y = mx". For inverse, I'm using the formula "y = k/x" or "xy = k"
5. The ideal gas law states the volume of a gas V varies, jointly with the number of molecules, M, and the temperature, T, and varies inversely with the pressure, P. If the constant of proportionality is 8.3, which of the following would represent the ideal gas law?
I believe that V varies directly with M and T, so this part of the formula would be:
. . .V = MT
but since it varies inversely with P and the constant is 8.3, I would understand the answer to be
. . .VP/MT=8.3
Could somebody please tell me if this is correct?
Thanks.7. The surface area of a cylinder varies jointly as the radius and the sum of the radius and the height. A cylinder with height 8 cm and radius 4 cm has a surface area of [96 times pi] cm^2. Find the surface area of a cylinder with radius 3 cm and height 10 cm.
To figure out this problem, I used a proportion. I did
. . .96pi / (4)(12) = Unknown Surface Area / (3)(13)
The 4 is the radius of the first cylinder and the 12 is the sum of the radius and the height.
The 3 is the radius of the second cylinder and the 13 is the sum of the radius and the height.
Then I finished working out the problem and the steps I used are as follows.
. . .(96pi)(3)(13) = (U)(4)(12)
. . .3744pi = 48U
. . .U = 78pi cm^2
So the answer I came up with for this problem was 78pi cm^2
