Hello.
I am teaching myself Calculus.
I am starting with differentiating simple algebraic expressions, and need a check / help, thanks!
\(\displaystyle \L y=x^{13}\)
\(\displaystyle \L y+dy = x+dx^{13}\) neglecting the small quantities of high order I get:
\(\displaystyle \L y + dy = x^{13} + 13x^{12}dx\)
subtract the original \(\displaystyle \L y = x^{13}\):
\(\displaystyle \L dy = 13x^{12}dx\)
divide both sides by dx
\(\displaystyle \L \frac {dy}{dx} = 13x^{12}\)
so, the change in y over the change in \(\displaystyle \L x = 13x^{12}\)
right?
now how would I do it for this: \(\displaystyle \L y = x^{ \frac {-3}{2}}\)
y + dy = 1/((x+dx)^(3/2))
I don't know where to go from here.
I am teaching myself Calculus.
I am starting with differentiating simple algebraic expressions, and need a check / help, thanks!
\(\displaystyle \L y=x^{13}\)
\(\displaystyle \L y+dy = x+dx^{13}\) neglecting the small quantities of high order I get:
\(\displaystyle \L y + dy = x^{13} + 13x^{12}dx\)
subtract the original \(\displaystyle \L y = x^{13}\):
\(\displaystyle \L dy = 13x^{12}dx\)
divide both sides by dx
\(\displaystyle \L \frac {dy}{dx} = 13x^{12}\)
so, the change in y over the change in \(\displaystyle \L x = 13x^{12}\)
right?
now how would I do it for this: \(\displaystyle \L y = x^{ \frac {-3}{2}}\)
y + dy = 1/((x+dx)^(3/2))
I don't know where to go from here.