Help creating algebra problem.

[elpeak]

My critera is below and my answer is in bold. Confirmation of the answer and or alternate solution(s) with any explanation are welcomed.

In a parking lot, there are 84 vehicles. All vehicles are either cars, trucks, or bicycles. There are twice as many trucks as bicycles, and twice as many cars as trucks.
Let t represent the number of trucks in the parking lot.


Answer: t + 2t + 4t = 84

 

[Deleted member 4993]

My critera is below and my answer is in bold. Confirmation of the answer and or alternate solution(s) with any explanation are welcomed.

In a parking lot, there are 84 vehicles. All vehicles are either cars, trucks, or bicycles. There are twice as many trucks as bicycles, and twice as many cars as trucks.
Let t represent the number of trucks in the parking lot.


Answer: t + 2t + 4t = 84

let

t = # of trucks

c = # of cars

b = # of bicycles

There are twice as many trucks as bicycles

Which number , between t and b, is smaller? (b) → t = 2 * b → b = t/2

twice as many cars as trucks.

Which number , between t and c, is smaller? (t) → c = t*2

In a parking lot, there are 84 vehicles

t + b + c = 84

t + t/2 + 2t = 84

 

[TchrWill]

In a parking lot, there are 84 vehicles. All vehicles are either cars, trucks, or bicycles. There are twice as many trucks as bicycles, and twice as many cars as trucks.

t = 2b

c = 2t = 4b

b + 2b + 4b = 84 making b = 12, t = 24 and c = 48 for a total of 84 vehicles.