If you'd been given "2 - 11y = 2", how would you solve for "y="? Do the same steps for the first equation.
If you'd been given "-6 + 3y = 9", how would you solve for "y="? Do the same steps for the second equation.
The only difference between solving linear equations in one variable (only x, say, or only y) and solving two-variable equations of the type you've posted, is that things won't simplify as much.
While, for "2 - 11y = 2", you can simplify the right-hand side of "-11y = 2 - 2" to get zero, you can't simplify as much for "2x - 11y = 2" when you subtract the x term over, yielding "-11y = 2 - 2x". But that's the only difference. You'll still divide through by -11 to isolate y. This will be the same for solving all literal equations.
That Khan Academy website is really excellent! Thanks for the link Denis.
So I've spent a little while still trying to get the hang of converting Ax+By=C into y=mx+b and I have pasted my working below.
I would greatly appreciate if someone could check if I've got it ok? I'm not the smartest guy in the world so I like to run my work past much more intelligent people to double check
For the first equation, I tried following an example but substituting my equation into it, I'm really not getting my head around this algebra stuff am I :???:
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