help asap please

[kayb]

Find a real number, k, such that -2x+ky-11=0 has y intercept 11

 

[Mrspi]

Find a real number, k, such that -2x+ky-11=0 has y intercept 11

The y-intercept is a point ON the y-axis. Every point on the y-axis has coordinates of the form (0, something). You're told that for this particular equation, the y-intercept is 11, so the graph crosses the y-axis at (0, 11).

You now have a value of 0 for x, and a value of 11 for y. Substitute those values for x and y in your equation:

-2x + ky - 11 = 0
-2(0) + k(11) - 11 = 0

Solve that equation for k.............

 

[Denis]

Find a real number, k, such that -2x+ky-11=0 has y intercept 11

Or arrange this way:
ky = 2x + 11 ; then:
y = (2/k)x + 11/k

What must k be in order for y-intercept 11/k to equal 11?