help again

[jeca86]

evaluate the integral

at the top the integral has 1 and at the bottom it has 0. the rest goes like this:

(x-1)/(x^2+3x+2)

so this is what i got:

separated into A/x+2 and B/x+1

A=3 and B=-2

then i plugged into the original problem. i was left with this:
3ln3-2ln2-3ln2+2ln1

i dont know if this is right. what do i do after this?

 

[Unco]

You're absolutely correct, Jeca.

ln(1)=0 and you could add the ln(2) terms to simplify, if you like.