Help again!

[jeca86]

Find the inverse equation of f(x)= ln(x+ (square root of (x^2 +1))).

My answer came out to be f^-1 (x)= 2lnx. I'm not sure if it's right.

 

[pka]

f(x)=y= ln(x+ √(x<SUP>2</SUP>+1)).
x=ln(y+ √(y<SUP>2</SUP>+1)).
e<SUP>x</SUP>=y+ √(y<SUP>2</SUP>+1).
Now someway you must solve for y.