Okay, this problem is algebra 2 but, I attempted to do some work on it but.... im stuck. It reads: the height of a diver jumping from a diving platform is about h= -16.1t^2 +11t+34.3
Where h is the height of the diver in feet above the water and t is the time measured in seconds, when diving from a platform about 34.3 feet above the water with an upward initial velocity of 11 ft/sec.
question: After how many seconds is the diver's height above the water 7 feet?
After how many seconds is the diver's height above water 36 feet?
*I set the whole thing up as an equation as I was taught in algebra 2 however, when I referred to my notes... we did not have 3 numbers on the right side of the equation... so, I attempted to solve it and I stopped at 27.3= -16.1t^2 +11t
Where h is the height of the diver in feet above the water and t is the time measured in seconds, when diving from a platform about 34.3 feet above the water with an upward initial velocity of 11 ft/sec.
question: After how many seconds is the diver's height above the water 7 feet?
After how many seconds is the diver's height above water 36 feet?
*I set the whole thing up as an equation as I was taught in algebra 2 however, when I referred to my notes... we did not have 3 numbers on the right side of the equation... so, I attempted to solve it and I stopped at 27.3= -16.1t^2 +11t
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