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The area bounded by the curve y = arctan x, the x-axis and the line x = 1 is rotated about the y-axis. Find the volume of the solid generated.

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Since this is being revolved about the y-axis, couldn't we use:

\(\displaystyle \L\\2{\pi}\int_{0}^{1}xtan^{-1}(x)dx\)

or possibly:

\(\displaystyle \L\\{\pi}\int_{0}^{\frac{{\pi}}{4}}(1-tan^{2}(y))dy\)
 
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