Have I re-arranged this correctly?

[thickmax]

Please can my re-arranging the equation steps be checked please?

f'(X_0) = f(X_0)/X_0-X_1
f'(X_0) * X_0 - X_1=f(X_0)
X_0-X_1=f(X_0)/f'(X_0)
-X_1=X_0+f(X_0)/f'(X_0)
X_1=X_0-f(X_0)/f'(X_0)


n_x is Number sub number


I think I have made it work, but I have been wrong many many times before, so I would like some clarification.

Many thanks

 

[ISTER_REG]

Do you have in the first line:
[MATH]f'(X_0) = \frac{f(X_0)}{X_0-X_1}[/MATH] or [MATH]f'(X_0) = \frac{f(X_0)}{X_0}-X_1[/MATH]
For the first case:
[MATH]f'(X_0) = \frac{f(X_0)}{X_0-X_1}[/MATH][MATH]f'(X_0)(X_0-X_1) = f(X_0)[/MATH][MATH]X_0-X_1 = \frac{f(X_0)}{f'(X_0)}[/MATH][MATH]X_0-\frac{f(X_0)}{f'(X_0)} = X_1[/MATH]

 

[thickmax]

The first one.

Thank you for clarifying! I wish they would show all the steps of re-arranging on the course I am doing!

Many thanks,
Max

 

[lex]

Please can my re-arranging the equation steps be checked please?

f'(X_0) = f(X_0)/X_0-X_1
f'(X_0) * X_0 - X_1=f(X_0)
X_0-X_1=f(X_0)/f'(X_0)
-X_1=X_0+f(X_0)/f'(X_0)
X_1=X_0-f(X_0)/f'(X_0)

f'(X_0) = f(X_0) / (X_0-X_1)
f'(X_0) * (X_0-X_1)=f(X_0)
X_0-X_1=f(X_0)/f'(X_0)
-X_1= - X_0+f(X_0)/f'(X_0)
X_1=X_0-f(X_0)/f'(X_0)