have a problem I keep getting the wrong answer
- Thread starter LN
- Start date
LN said:
If you had posted your work and the wrong answer, we could much more quickly see just what the problem is. Without that, it's a guessing game.
The most likely problem is misinterpretation of items in and outside parentheses. For example, on the left side, what is that "-2"? Is that supposed to be an exponent, or a -2 tagged onto the LN7[2-(3+4r)]?
Hello, LN!
If you don't show us your work, we can't tell you what you're doing wrong ... duh!
The right answer is \(\displaystyle r\,=\,1\) . . . but, of course, you know that, right?
I'll do the whole problem for you
\(\displaystyle \;\;\) and you'll answer, "Oh, I forgot the minus.
\(\displaystyle \;\;\) or worse . . . "I was looking at the wrong answer ...hahaha!"
Okay, I'll do it for you . . . just this once.
We are given: \(\displaystyle \L\;7[2\,-\,(3\,+\,4r)]\,-\,2\;=\;-9\,+\,2(1\,-\,15r)\)
The left side is: \(\displaystyle \:7[2\,-\,3\,-\,4r]\,-\,2\;=\;7[-1\,-\,4r]\,-\,2\;=\;-7\,-\,28r\,-\,2\;=\;-28r\,-\,9\)
The right side is: \(\displaystyle \:-9\,+\,2\,-\,30r\;=\;-7\,-\,30r\)
The equation becomes: \(\displaystyle \L\;-28r\,-\,9\;=\;-7\,-\,30r\)
Can you finish it now?
If you don't show us your work, we can't tell you what you're doing wrong ... duh!
The right answer is \(\displaystyle r\,=\,1\) . . . but, of course, you know that, right?
I'll do the whole problem for you
\(\displaystyle \;\;\) and you'll answer, "Oh, I forgot the minus.
\(\displaystyle \;\;\) or worse . . . "I was looking at the wrong answer ...hahaha!"
Okay, I'll do it for you . . . just this once.
We are given: \(\displaystyle \L\;7[2\,-\,(3\,+\,4r)]\,-\,2\;=\;-9\,+\,2(1\,-\,15r)\)
The left side is: \(\displaystyle \:7[2\,-\,3\,-\,4r]\,-\,2\;=\;7[-1\,-\,4r]\,-\,2\;=\;-7\,-\,28r\,-\,2\;=\;-28r\,-\,9\)
The right side is: \(\displaystyle \:-9\,+\,2\,-\,30r\;=\;-7\,-\,30r\)
The equation becomes: \(\displaystyle \L\;-28r\,-\,9\;=\;-7\,-\,30r\)
Can you finish it now?