Hard percentage problem

Love21

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Jan 18, 2008
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There are 75 more women than men enrolled in Linden College. If there are 'n' men enrolled, then in terms of n, what percent
of those enrolled are men?

(a) n/n + 75 %
(b) n/ 2n + 75 %
(c) n/ 100(2n + 75) %
(d) 100n / n + 75 %
(e) 100n/ 2n + 75 %

So I think I should plug in a number for 'n' such as 100, and then obviously plug that into the answer choices...but the answer choices
have to match some kind of conclusion found in the question, so how do i figure out what percent of those enrolled are men
 
I would suggest you figure out the PROCESS of obtaining the answer when you plug in a number.

For instance, suppose we say there are 50 more women than men and we want to know the percent of those enrolled that are men and there are 300 men enrolled.

That means there are 300+50 = 350 women enrolled. So the total enrollment is 300+50+300 = 650. So, our problem becomes "the number of men enrolled is what percent of the total enrollment?" or 300 is what percent of 650? To get that, of course, we divide 300 by 650 and convert the obtained decimal to a percent. Hope that helps.
 
Unless I'm missing something, none of the choices are correct. I get 100n/(2n+75) %. Where did I go wrong?
 
Loren said:
I get 100n/(2n+75) %. Where did I go wrong?
Since you did not show your work or reasoning, I'm afraid it is not possible to find where you made your error. Sorry! :oops:

Eliz.
 
Loren said:
Unless I'm missing something, none of the choices are correct. I get 100n/(2n+75) %. <-- That's choice 'e' (of course written in a funky way)

Where did I go wrong?
 
100n/ 2n + 75 % and 100n/(2n+75) % are not the same.

Let's try n=5.

100n/ 2n + 75 = 100*5/2*5+75 = 500/2*5+75 = 250*5+75 = 1250 + 75 =1325

100n/(2n+75) = 100*5/(2*5+75) = 100*5/(10+75) = 100*5/85 = 500/85 = 5.882352941...

I stand by my previous response.
 
Loren said:
100n/ 2n + 75 % and 100n/(2n+75) % are not the same.

Let's try n=5.

100n/ 2n + 75 = 100*5/2*5+75 = 500/2*5+75 = 250*5+75 = 1250 + 75 =1325

100n/(2n+75) = 100*5/(2*5+75) = 100*5/(10+75) = 100*5/85 = 500/85 = 5.882352941...

I stand by my previous response.

I'm guessing that there was some "sloppy typing" of the answer choices.

total enrollment = 2n + 75

100[ n / (2n + 75)] % should be the percent of men.
 
100[ n / (2n + 75)] and 100n / (2n + 75) are the same.

It seems to me that too many of us have forgotten about the Order of Operations Convention. Without it, confusion reigns.
 
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