graphs: does graph of 1 + e^2 have asymptote at y = 1?

[tinad]

Does the graph f(x)=1+e^x have a horizontal asymptote at y=1?

I get that e^x = 0 so you're left with 1. If e^x = 0 then e^0 = 1. Would it have an inflection point at (0,2)?

 

[skeeter]

f(x) = 1 + e^x has a horizontal asymptote at y = 1.

it does not have any points of inflection ... f(x) is concave up throughout its entire domain because f"(x) = e^x > 0 for all x.