Graphing reciprocal functions: f(x) = x + 2

[fred2028]

So I'm stuck on this.

9a) Graph f(x)=1/(x+2) by first graphing f(x)=x+2.

What I have so far: I know that there is an asymptote at x=-2. Apart from a table of values, how else can I graph this?

 

[arthur ohlsten]

y=x+2 a straight line slope 1, y intercept 2

y=1/[x+2] assymptotes at x=-2 and y=0
the curve is symetric about the line y=x+2
the curve crosses the line at : 1/[x+2]= x+2
1=[x+2]^2
+/-1=x+2
x=-3 x=-1
but if x=-3 y=1/[-3+2] y=-1
and if x=-1 y=1/[-1+2] y=1

point of intercept -3,-1 and -1,1

Arthur