Graphing quadratic function over limited interval

Connie

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Oct 6, 2006
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I am having trouble understanding problems like the following:

Graph y= x^2 - 2x + 1 for -2 <= x <= - 4.

How would I graph this, using x-values in the indicated interval? And how would I find the equation for the axis of symmetry?
 
Graph y= x^2 - 2x + 1 for -2 <= x <= - 4.

How would I graph this, using x-values in the indicated interval? And how would I find the equation for the axis of symmetry?
Simply graph the equation as usual (it’s a parabola). Just don’t graph any of the parabola that lies outside your interval.

For any quadratic of the form y = ax^2 + bx + c, the equation of the axis of symmetry is

x = -b/2a
 
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