graphing linear equations

funnylyn

New member
Joined
Jan 11, 2006
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2
How do I graph this?

y=1/7x-2

1/7 (fraction)

i think this equation is Y=mx+b. But i don't know how to solve it and put it on a graph.

Do i have to do intercepts or change symbols?
 
i really need help i checked all over the internet but couldn't find anything...my teacher didn't really explain!
 
Y and X - not needed for the process, just make sure they are there
b - this is where the line goes through the y axis, so you know a point on the line must be (0, b). if there is no b the line goes through the origin
m = slope of the line. if m = 4/5 you can graph the line by moving up "4" over "5" from where you graphed (0,b). remember.. "rise over run"
 
here's how I do it

when you have y=mx+b
the coordinates of the y intercept are always (0,b)
and the slope is m

For example: y= 5/4x+6
b=6 so y int. is (0,6). Now find that point on the coordinate plane.
Notice the slope m. M is always a fraction, even when it is written as an integer, say y=3x, the 3 can be written as 3/1.

Now, think of the numerator (top) as the "rise" and the denominator (bottom) as the run.. that is to say, the top of the fraction indicates how much "up" to go and the bottom indicates how much to the right you go. In the case of y=5/4x+6, the rise is 5 and the run is 4. So, starting at the y intercept, move 5 unites up and 4 units to the left.

Now, apply this to your problem:D
 
Re: here's how I do it

Coraelle said:
Notice the slope m. M is always a fraction, even when it is written as an integer, say y=3x, the 3 can be written as 3/1.

Now, think of the numerator (top) as the "rise" and the denominator (bottom) as the run.. that is to say, the top of the fraction indicates how much "up" to go and the bottom indicates how much to the right you go. In the case of y=5/4x+6, the rise is 5 and the run is 4. So, starting at the y intercept, move 5 unites up and 4 units to the left. <-----since the run is +4, the move of four units should be to the RIGHT.

Now, apply this to your problem:D
 
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