Re: graphing linear equations
There is more than one approach to your problem. Not knowing which approach you might use, I will just ask you if you can find two different points that satisfy the equation? If you can do that, then plot those points and draw a straight line through them.
For instance, if you had the equation 3x+2y=12 you could determine that the points (0,6) and (4,0) satisfy the equation in that 3(0)+2(6)=12 and 3(4)+2(0)=12. So, you plot those two points on the graph and draw a straight line through them.
Others might rewrite the equation as y=-(3/2)x+6. This would tell them that the y-intercept is 6 and the slope of the line is -3/2. This would allow them to draw a straight line through (0,6) with a slope of -3/2.
There are two of the many possible approaches.
