graphing inequalities

H

HeLp 911

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Jan 12, 2006
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absolute of I 5x-2 I less than or equal to 6

My answer I got was (-infin,-4/5) U (8/5, infin) But this seems to be backwards? Any suggestions ?
 
Your subject line refers to graphing, but then you posted an inequality instead of a function...?

You ask if your "answer" is correct, but you forgot to include the instructions. What is the question to which your answer applies? When you reply, please clarify what you mean by your answer being "backwards".

Thank you.

Eliz.
 
It says to solve the inequality. Express the solution using interval notation and graph the solution set.

The problem is I 5x-2 I is less than 6[/code]
 
That is indeed backwards.
Look at x=0: |-2|=2<6? true
Look at x=-10: |-52|=52<6? false
Look at x=10: |48|=48<6? false
You don't show your work so we can't say why it became reversed.
 
HeLp 911 said:
It says to solve the inequality. Express the solution using interval notation and graph the solution set.

The problem is I 5x-2 I is less than 6[/code]
Click to expand...

If I understand your problem correctly, it is

| 5x - 2 | < 6

An absolute value can be thought of as "distance from 0". So, if we say that the absolute value of "something" is less than 6, we are saying that "something" must be less than 6 units from 0. That "something," then, must lie between 6 and -6.

In your problem, the "something" is 5x - 2. And (5x - 2) must lie between 6 and -6. So,

5x - 2 < 6 AND 5x - 2 > -6

Solve each of those, and remember that in an AND statement, BOTH conditions must be true at the same time. I think this will resolve your "backwards" difficulty.
 
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