Hello, kimbero5!
How would i graph the equation y = e<sup>-(x+3)</sup>
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They expect you to be familiar with the graph of: y = e<sup>x</sup> . . . Let's call it "G".
. . And they expect you to know what the "modifications" do to the graph.
In general, y = e<sup>x-a</sup> looks like "G", but moved <u>a</u> units to the right.
Also, y = e<sup>-x</sup> looks like "G", but "flipped" over the y-axis (a left-right reflection).
Your graph is: y = e<sup>-(x+3)</sup>
. . In the parentheses, we have: x - (-3)
. . We have "G", moved 3 units to the <u>left</u>.
. . Sketch that graph.
Then the exponent has a "minus".
. . Your graph is reflected over the y-axis.
. . Sketch that graph.
And <u>that</u> is your answer.