calculus101
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- Jun 14, 2020
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Hi! Could anyone solve this equation for me?
(lnx)^3 + (x) (3(lnx)^2) (1/x) = 0
Thank you!
(lnx)^3 + (x) (3(lnx)^2) (1/x) = 0
Thank you!
What makes it urgent? Are you sitting form the exam right this moment?
Have you considered the simplification of [math](x) (something) (1/x)[/math]?
Did you notice that it is equivalent to \((\log(x))^3 + (3(\log(x))^2) = 0\) the \(x's\) divide off.Hi! Could anyone solve this equation for me?
\((\log(x))^3 + (3(\log(x))^2) (1/x)(x) = 0\)
It is a sad day for the calculus when algebra gets in your way of learning.
Let's recall the commutative property of multiplication. A*B*C = A*C*B. Yes?
Did you notice that it is equivalent to \((\log(x))^3 + (3(\log(x))^2) = 0\) the \(x's\) divide off.
One solution is \(x=1\).
Some people use log(x) to mean ln(x). In this thread, you may read both notations to mean the natural logarithm.Can I ask why ln changed to log? Are they the same thing?