The acceleration function a(t) in m/s^2, a(t)=2t + 4, 0<equal to(t) <equal to 3
initial velocity v(0), both are given for a particle moving along a line v(0)=-5
find v(t) at time t, and find the distance d traveled during the time interval?
So I took the integral of a(t)which is = t^2 +4t to find v(t) and 18m/s and the distance would be 18 X 3sec. -v(0)=54-5=49m
Where did I go wrong?
Thanks,
Michele
initial velocity v(0), both are given for a particle moving along a line v(0)=-5
find v(t) at time t, and find the distance d traveled during the time interval?
So I took the integral of a(t)which is = t^2 +4t to find v(t) and 18m/s and the distance would be 18 X 3sec. -v(0)=54-5=49m
Where did I go wrong?
Thanks,
Michele