Given an expression for E, how do I incorporate dt to arrive at dE/dt?

cloudy387

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"By shrinking, the amount of energy Erad that the Sun can radiate into space is [MATH]E_{rad}=\frac{1}{2}\Delta U=(\frac{3}{10})\frac{GM^{2}}{R}\approx 10^{41}[/MATH] Joules. The other half of the energy goes into internal heating.

Exercise : By how much would the Sun have to shrink per year in order to maintain its present luminosity? Hint: Differentiate the expression for Erad (assuming that the mass of the Sun remains constant), set dErad/dt = LSun and show that dR/dt = -2.4E(-6) m/s."

The Erad expression was preceded by an expression for [MATH]\Delta U=-\frac{3GM^{2}}{5}[\frac{1}{R_{0}}-\frac{1}{R}][/MATH], which is used to determine the change in the Sun's gravitational binding energy as it contracts from some initially large radius R0 to its currently observed radius R < R0.

I am stuck at the very first part: differentiating Erad to arrive at an expression for dErad/dt. My question is how do I incorporate time (dt) into this? I know I must arrive at a timescale of seconds. I tried using the definition of the derivative because I knew that would allow me to factor the 3GM2/10 out of the limit expression, but I'm not getting far at all.
 
I'm not sure of some details here, but it looks like you may just be missing the chain rule.

If we write the equation as E = A/R, where A = 3GM^2/10, then dE/dt = d/dt(AR^-1) = (-AR^-2)dR/dt.

Can you take it from there?
 
Wow! I'm getting there but may need just a bit more help yet. For kicks I went ahead and solved for dR/dt in your expression and am getting the correct answer (thank you!!) but I'm having trouble seeing what happened to my inner derivative here.

I will work this just as I would on a sheet of scratch paper on an exam:

E = A/R = AR-1
let A = 3GM2/10
A' = ?
dE/dA = -AR-2 * A'

And here I think I'm not seeing something: the value for A in this problem never changes, so my gut says A'=0, but that leaves me stuck.
 
I think I might be getting somewhere. Looking the above over, I see I'm missing the product rule, or at least I wasn't properly acknowledging it before now!

E = AR-1
dE/dt = (A')(R-1) + (A)(-R-2)(dR/dt)
The first term on the right goes away because A' = 0 and then I'm left with:
dE/dt = (-AR-2)(dR/dt)
dE/dt ÷ -AR-2 = dR/dt

The hint in the exercise gave us a value for dE/dt and so after plugging in everything back in I'm left with the correct value for dR/dt! Thank you, Dr.Peterson!
 
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Right, A is a constant, so it can just be pulled outside the derivative. If it were not, you would have to use the product rule -- which you didn't do! That's why what you got made no sense.

Also, you are not differentiating with respect to A! Why did you write dE/dA? You want dE/dt.

Rather, R is a function of t, so dE/dt = dE/dR * dR/dt. Try that.
 
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