geometry help!! area of polygons..

CJS525

New member
Joined
May 8, 2006
Messages
3
i really dont understand this... if someone could explain it, that'd be amazing.. i've got 3 problems to show what i need help with.. thanks! :eek:
145241609.jpg
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find the apothem, side legnth, perimeter and area. thats all, i hope that helps!
 
Hello, CJS525!

I assume these are all regular polygons
    \displaystyle \;\;and that the interior point is the "center" of the figure.

Here's a start . . .
Code:
                  *
                 / \
                /   \
               /     \
              /       \
             /         \
            /           \
           /      B      \
          /       *       \
         /  8  *  |        \
        /   *     |         \
       / * 30°    |          \
     A* - - - - - + - - - - - *
                  C

In right triangle ABC\displaystyle ABC, we have: BAC=30o,  AB=8\displaystyle \,\angle BAC\,=\,30^o,\;AB\,=\,8
Hence: BC=4,  AC=43\displaystyle \,BC\,=\,4,\;AC = 4\sqrt{3}

S=83\displaystyle S\:=\:8\sqrt{3}

a=4\displaystyle a\:=\:4

P=3×83=243\displaystyle P\:=\:3\,\times 8\sqrt{3}\:=\:24\sqrt{3}

A=34S2=483\displaystyle A\:=\:\frac{\sqrt{3}}{4}S^2\:=\:48\sqrt{3}
 
awesome... thanks so much! i've got a test on this tomorrow... thanks! :eek:
 
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