Geometry: finding angles of elevation and depression

rachelmaddie

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I’m not sure if my calculations are correct for solving angles of elevation and depression
 
1.) From the given information we may write:

[MATH]\tan(49^{\circ})=\frac{h}{400\text{ ft}}\implies h=400\tan(49^{\circ})\text{ ft}\approx460.1473628884\text{ ft}[/MATH]
2.) [MATH]\theta=\arctan\left(\frac{12.5}{18}\right)\approx34.8^{\circ}[/MATH]
You are finding an angle, so your units will be degrees, not meters. Same with 3.), your unit is wrong, but the calculation correct.

4.) You want to begin with

[MATH]\tan(19^{\circ})=\frac{120\text{ ft}}{x}[/MATH]
 
1.) From the given information we may write:

[MATH]\tan(49^{\circ})=\frac{h}{400\text{ ft}}\implies h=400\tan(49^{\circ})\text{ ft}\approx460.1473628884\text{ ft}[/MATH]
2.) [MATH]\theta=\arctan\left(\frac{12.5}{18}\right)\approx34.8^{\circ}[/MATH]
You are finding an angle, so your units will be degrees, not meters. Same with 3.), your unit is wrong, but the calculation correct.

4.) You want to begin with

[MATH]\tan(19^{\circ})=\frac{120\text{ ft}}{x}[/MATH]
Thank you!!
 
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