Geometry...checking

[HomeWork14]

Hello,

Can someone please tell me if I worked this out correct and ended with the right answer?

Thank You...

I need to find the area and Height of this right triangle ( only knowing the lengths of its sides)side 6,5,11...

Is this correct? :?:

sides 6, 5, 11
--
6+11+5/ 2
=22/2=11

A< 11 (11-5) (11-6) (11-11)>
=11 . 6 . 5 = 330

sqare root of 330 = 18.2
Area = 18.2
------
1/2 base 11 = 5.5

5.5 / 18.2 = 3.3

Height = 3.3
---------

Area= 18.2
Height= 3.3

 

[arthur ohlsten]

I am having trouble understanding your problem

A right triangle of sides 5 and 6 would have a hypoteneuse of C^2=A^2+B^2
C^2=5^2+6^2
C^2=25+31
C=sqrt 56
C=7.49 not 11 as given in your problem


Also if two sides of a triangle are 5,6 the third side can only be 11 [the sum of 5,6]
if the "triangle" is a straight line. The area would be 0

Arthur

 

[Deleted member 4993]

Hello,

Can someone please tell me if I worked this out correct and ended with the right answer?

Thank You...

I need to find the area and Height of this right triangle ( only knowing the lengths of its sides)side 6,5,11...Not a right-triangle

Is this correct? :?: ...No...

sides 6, 5, 11
--
6+11+5/ 2
=22/2=11

A< 11 (11-5) (11-6) (11-11)> = 11 * 6 * 5 * 0 = 0
=11 . 6 . 5 = 330

sqare root of 330 = 18.2
Area = 18.2
------
1/2 base 11 = 5.5

5.5 / 18.2 = 3.3

Height = 3.3
---------

Area= 18.2
Height= 3.3

 

[arthur ohlsten]

no! I BELIEVE YOU ARE WRONG

if one side is 5, and the other is 6, then they must lay end to end to have the third "side" 11

5,6,11 forms a straight line , or a triangle of area 0

Arthur

 

[Denis]

Arthur, Subhotosh is saying SAME thing you are :idea: