Geometry: Angle Pairs

rachelmaddie

Full Member
Joined
Aug 30, 2019
Messages
851
Find m<y if m<y is six more than three times its complement.
Question 1 options:

43.5

21

136.5

69
 
Yes, so given this, and the problem statement, we may write:

[MATH]y=3(90-y)+6[/MATH]
What do you get upon solving for \(y\)?
 
Yes, so given this, and the problem statement, we may write:

[MATH]y=3(90-y)+6[/MATH]
What do you get upon solving for \(y\)?
y = 6 + 3(90 - y)....This is your equation. We can now solve for y using algebra.
y = 6 + 270 - 3y
y = 276 - 3y
y + 3y = 276
4y = 276
y = 276/4
y = 69
 
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