Generalized power rule: Find critical pts of g=3x^4+8x^2-24

[lauren52]

I am having trouble factoring and finding the critical points.
g(x) = 3x^4+8x^2-24
g'(x) = 12x^3+16x
= 12x^3+16x=0
= 4x(3x^2+4)=0

4x+0 I am unsure of the next step regarding what's left in parenthesis (3x^2+4)

 

[Deleted member 4993]

Re: Generalized power rule

I am having trouble factoring and finding the critical points.
g(x) 3x^4+8x^2-24
g'(x) 12x^3+16x
12x^3+16x=0
4x(3x^2+4)=0

4x+0 I am unsure of the next step regarding what's left in parenthesis (3x^2+4)

Your one solution is

4x = 0

x = 0

other one

3x^2 + 4 = 0

x^2 = - 4/3 <<<<<< no solution becuse a square is alsways positive in real domain.

 

[lauren52]

Re: Generalized power rule

Thank you