alexedward
New member
- Joined
- Oct 5, 2010
- Messages
- 5
I was asked to differentiate the function h(x) = g / (f^2+g), using the quotient law. I did so, and ended up with this:
h'(x) = [g'(f^2+g) - (2f' + g')(g)] / [(f^2+g)]^2.
When I asked a T.A if this was correct, they said no. According to them, the part in the numerator that reads (2f' + g')(g) should actually be (2ff' + g')(g) (there is a prime symbol beside the second f, and the first g). I know what the T.A is telling me is correct, since it got me the right answer..but why do you do this? Is this different from the derivative of x^2, which is 2x?
h'(x) = [g'(f^2+g) - (2f' + g')(g)] / [(f^2+g)]^2.
When I asked a T.A if this was correct, they said no. According to them, the part in the numerator that reads (2f' + g')(g) should actually be (2ff' + g')(g) (there is a prime symbol beside the second f, and the first g). I know what the T.A is telling me is correct, since it got me the right answer..but why do you do this? Is this different from the derivative of x^2, which is 2x?