Gauss-Jordan Elimination Method

[traunit]

I missed a couple of days of class.

Can someone help me with this problem?

Solve for X,Y, Z, & W using the Gauss-Jordan Elimination Method

5x+3y+z+5w=-2
3x+2y+2z+4w=2
2x+4y+3z-3w=-11
4x-3y-2z+2w=-3

Thanks....

 

[stapel]

I missed a couple of days of class.

Unfortunately, we cannot replicate those hours of classroom instruction within this environment. If you're having trouble following the procedure from the worked examples in your textbook and the copies of classnotes you've obtained, then try working through a few lessons online.

. . . . .Google results for "gauss-jordan elimination"

Once you have caught up on the missing material, please attempt the exercise. If you get bogged down in the middle, or aren't sure if you followed the process correctly, please reply showing all of your work and reasoning.

Thank you.

Eliz.

 

[tkhunny]

Use row operations to eliminate multiple appearances of variables. I'll do the first column. Warning: There is very little 'clean' about it. The hardest part is paying attention, I think.

R1: 5x+3y+z+5w=-2
R2: 3x+2y+2z+4w=2
R3: 2x+4y+3z-3w=-11
R4: 4x-3y-2z+2w=-3

R4 - 2*R3 ==> New R4

R1: 5x+3y+z+5w=-2
R2: 3x+2y+2z+4w=2
R3: 2x+4y+3z-3w=-11
R4: 0x-11y-8z+8w=19

R1 - R2 - R3 ==> New R1

R1: 0x-3y-4z+4w=7
R2: 3x+2y+2z+4w=2
R3: 2x+4y+3z-3w=-11
R4: 0x-11y-8z+8w=19

R2 - R3 ==> New R2

R1: 0x-3y-4z+4w=7
R2: 1x-2y-1z+7w=13
R3: 2x+4y+3z-3w=-11
R4: 0x-11y-8z+8w=19

R3 - 2*R2 ==> New R3

R1: 0x-3y-4z+4w=7
R2: 1x-2y-1z+7w=13
R3: 0x+8y+5z-17w=-37
R4: 0x-11y-8z+8w=19

There. See how clean the x-coefficients are? Now do it for the y-coefficients.

Note: I went through this rather quickly as I was typing it. If you find an arithmetic error, you get bonus points (unless there really isn't an error).

 

[traunit]

Thanks tkhunny...

I googled this and read the lesson chapter but it still looked confusing, something about turning the numbers into zeroes. I am going to try this problem again before class.