g(x) = (4x) / (x^2 + 1): find the inflection points

[lonesoui]

I am so greatful that there are forums like these around for problems I just seem to break. I'm trying to get the inflection points on this function:

g(x) = (4x)/(x^2+1)

My relative min is at x= -1 and rel max is at x = 1, and 1 of the 3 inflection points is at (0,0), and there are 2 others but I can't seem to understand how to solve for it. Getting the the second derivative has gotten me thus far:

g''(x)= -24x/(x^2+1)^2 + 8x^2(4x^3 = 4x)/(x^2+1)^4

and then i'm stuck. My calculator shows me where it is, but how exactly do I achieve them?

 

[stapel]

g''(x)= -24x/(x^2+1)^2 + 8x^2(4x^3 = 4x)/(x^2+1)^4

I'm sorry, but I can't guess what you might mean by this...? For instance, how does an "equals" sign end up inside a set of parentheses...?

Please reply with a clear listing of all of your steps and reasoning, so we can see what you are doing and how you arrived at the above result. Thank you!

Eliz.

 

[lonesoui]

I fat fingered it! it's suppose to be a + sign