g(n) and h(n)

A

anp

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Jun 20, 2009
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g(n)= n^2 + n
h(n)=n^2-n

using those functions g(5) -h(4)=

i tried plugging in the 5 and the 4 into the functions for n but im guessing thats not how you do it because it wasnt an anwer choice.

and then based of of those again which is equivalent to h(m+1)?
a- g(m)
b- g(m) +1
c- g(m)-1
d- h(m)+1
e h(m)-1

i dont even know how to start this...
 
First solve each part separately...

g(n) = n^2 + n
so: g(5) = 5^2 + 5
g(5) = 25 + 5
g(5) = 30
then...

h(n) = n^2 - 4
so: h(4) = 4^2 - 4
h(4) = 16 - 4
h(4) = 12

Therefore:
g(5) - h(4) = 30 - 12
which = 18

I know I put in steps that you are going "duh" to, but I just wanted you to see the flow of solving the problem. I hope this helps. :)
 
thanks that did help! and yeah...duh. but the one i really didnt get was the second problem..
 
So now you tell us:

h(m+1) = (m+1)[sup:3785v41a]2[/sup:3785v41a] - (m+1) = ???

and

g(m+1) = (m+1)[sup:3785v41a]2[/sup:3785v41a] + (m+1) = ???

Then look and match
 
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