fxn is dicontinuous

We all will have trouble with it until we know the actual problem statement.
 
Find all values of x=a where the fxn is discontinuous

I found the answer to be -2 and 6 but not sure if that is right
 
Find all values of x=a where the fxn is discontinuous

I found the answer to be -2 and 6 but not sure if that is right
Click to expand...
Discontinuity occurs where a function is not defined, not when the function is zero.

f(x) will not be defined when the denominator is zero. So you are correct in saying at x=6 there is discontinuity.

When x=-2, f(x) =0. This is defined.

Note that if you wanted to find the x-ordinates when f(x)=0, you would factorise the quadratic in the numerator:

f(x) = |x^2-4|/(x-6) = |(x+2)(x-2)|/(x+6). So f(x) =0 when x=-2 and when x=2.
 
So the answer is just 6 because it is not defined and -2 is defined so it is not discont.

Thanks :lol:
 
You must log in or register to reply here.
Top