I have another question on this problem. I think I have the right formula, I'm just unsure of really what i'm looking for here.
A stretched wire vibrates in it's fundamental mode at a frequency of 657 vibrations/s. What would be the fundamental frequency if the wire were half as long, with twice the diameter and with 5.8 times the tension? Answer in units of Hz.
The only formula I could find that is for fundamental frequency is
fn= n (v/2L) = n/2Lsquare root Fr/u= nf1
A stretched wire vibrates in it's fundamental mode at a frequency of 657 vibrations/s. What would be the fundamental frequency if the wire were half as long, with twice the diameter and with 5.8 times the tension? Answer in units of Hz.
The only formula I could find that is for fundamental frequency is
fn= n (v/2L) = n/2Lsquare root Fr/u= nf1