functions

[knaub]

I need to figure out the rule to these two function tables

1 - 65
2 - 90
3 - 115
4 - 140

the other one is

1 -10
2 - 16
3 - 22
4 - 28

 

[Deleted member 4993]

I need to figure out the rule to these two function tables

1 - 65
2 - 90
3 - 115
4 - 140

the other one is

1 -10
2 - 16 = 10 + 6
3 - 22 = 16 + 6 = 10 + 2*6
4 - 28 = 22 + 6 = 10 + 3*6

Now your turn......

Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.

 

[Lost souls]

I need to figure out the rule to these two function tables

1 - 65
2 - 90
3 - 115
4 - 140

the other one is

1 -10
2 - 16
3 - 22
4 - 28

What i do in such cases is this. .let the LHS of the above functions be x.then y(values on the right hand side of your table) is the result after application of the function . .Check if 'y' for the different values of "x" are in Arithmetic Progression. .i.e. each term differs from the succeeding term by a constant amount. .

Now for the second problem, the common difference is 6. .that means when x=0, y= 4(subtract 6 from the first value of y, i.e 10). .notice that for each value of x, 6 is added x times to 4 to get y. .
hence y= 4 + 6x.

 

[stapel]

What i do in such cases is this. .let the the LHS of the above functions be x....

Note to original poster: The abbreviation "LHS" in the above reply stands for "left-hand side". In this case, "LHS" indicates the "1, 2, 3, 4" columns in your tables.

 

[Lost souls]

Note to original poster: The abbreviation "LHS" in the above reply stands for "left-hand side". In this case, "LHS" indicates the "1, 2, 3, 4" columns in your tables.

yeah. .that. .

 

[soroban]

Hello, knaub!

I need to figure out the rule to these two function tables:

. . \(\displaystyle \begin{array}{|c|c|} \hline x & f(x) \\ \hline 1 & 65 \\ 2 & 90 \\ 3 & 115 \\ 4 & 140 \\ \hline \end{array}\)

Take the difference of consecutive terms.

\(\displaystyle \begin{array}{c|ccccccc}\text{Sequence} & 65 && 90 && 115 && 140 \\ \hline \text{Difference} && 25 && 25 && 25 \end{array}\)


We see that the terms "go up by 25".

The formula is: .\(\displaystyle f(x) \:=\:40 + 25x\)

The other one is:

,. . \(\displaystyle \begin{array}{|c|c|} \hline x & f(x) \\ \hline 1 & 10 \\ 2 & 16 \\ 3 & 22 \\ 4 & 28 \\ \hline \end{array}\)

Take the difference of consecutive terms.

\(\displaystyle \begin{array}{c|ccccccc}\text{Sequence} & 10 && 16 && 22 && 28 \\ \hline \text{Difference} && 6 && 6 && 6 \end{array}\)


We see that the terms "go up by 6".

The formula is: .\(\displaystyle f(x) \:=\:4 + 6x\)