h(x) = x/2x + 15
Your typing means this:
\(\displaystyle h(x) \;=\; \frac{x}{2} \cdot x \;+\; 15\)
Perhaps, the given function h is supposed to be this:
\(\displaystyle h(x) \;=\; \frac{x}{2x \;+\; 15}\)
If this is the case, then we type grouping symbols around the denominator to show it:
h(x) = x/(2x + 15)