Functions

soprano

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Jan 29, 2010
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I need help with this.

A ball is propelled upward from ground level. After 't' seconds, its height in feet is a function defined by f(t)=-16t^2+112t.
After how many seconds will it reach a height of 192 feet?
 
soprano said:
I need help with this.

A ball is propelled upward from ground level. After 't' seconds, its height in feet is a function defined by f(t)=-16t^2+112t.
After how many seconds will it reach a height of 192 feet?

The coordinates at the 192 feet will be (t, f(t)) which will be (t, 192), since 192 feet is a function of time.

f(t)=16t2+112t\displaystyle f(t)=-16t^2+112t

192=16t2+112t\displaystyle 192=-16t^2+112t

16t2112t+192=0\displaystyle 16t^2-112t+192=0

t27t+12=0\displaystyle t^2-7t+12=0

I'll leave the rest to you. There will be two times when the ball will be at 192 feet. Once going up and again coming back down.
 
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