Functions

[kjones]

Consider the function h(x) =

x^2 - 1 for x less than -1

x+1 for -1 less than or equal to x less than 3

3 + the square root of x-2 for x greater than or equal to 3.

I need to find these vales:

a) h(-1) = (-1) + 1

b) h(0) = (0) + 1

c) h(-2) = (-2) ^2 -1

d) h(6) = 3 + the square root of 6 - 2


THANKS!
K

 

[soroban]

Hello, K!

Consider the function: \(\displaystyle \,h(x) \;=\;\left\{\begin{array}{ccc}x^2\,-\,1 & x\,<\,-1 \\ x + 1 & -1\,\leq\,x\,<\,3 \\ 3 + \sqrt{x-2} & x\,\geq\,3\end{array}\)

I need to find these values:

\(\displaystyle a)\;h(-1) \;=\;(-1)\,+\,1\)

\(\displaystyle b)\; h(0) \;= \;0\,+\,1\)

\(\displaystyle c)\;h(-2) \;= \;(-2) ^2\, -\,1\)

\(\displaystyle d)\; h(6) \;= \;3\,+\,\sqrt{6 - 2}\)

Your work is correct . . . so far.

But why didn't you finish the problems?

\(\displaystyle a)\;-1\.+\.1\;=\;0\)

\(\displaystyle b)\;0\,+\,1\;=\;1\)

\(\displaystyle c)\;4\,-\,1\;=\;3\)

\(\displaystyle d)\;3\,+\,\sqrt{4}\;=\;5\)

 

[kjones]

Thanks for your help. I had those answers...but wasn't sure about them.

K