Functions are odd, even, or neither??

[romanianxromo]

(a) f(x) = x²/?x²+ 1

(b) g(x) = x^3 - ? x- 7

I think my answers might be correct. For (a) I took f(-x) and got

f(-x)= (-x)²/?(-x)² + 1 and got ... x²/?x²+ 1 which is the original equation, so is it even then?

For (b) I took -g(x) and got

-g(x)= - (x³- ?x-7)
-x³ + ?x+7 is not odd

Then I took g(-x) and got

(-x)³ - ?x-7
-x³ - ?x-7 is not even , so it must be neither then? right?

 

[Deleted member 4993]

(a) f(x) = x²/?x²+ 1

(b) g(x) = x^3 - ? x- 7

I think my answers might be correct. For (a) I took f(-x) and got

f(-x)= (-x)²/?(-x)² + 1 and got ... x²/?x²+ 1 which is the original equation, so is it even then?<<<<< Correct

For (b) I took -g(x) and got

-g(x)= - (x³- ?x-7)
-x³ + ?x+7 is not odd

Then I took g(-x) and got

(-x)³ - ?x-7 <<<< This should be (-x)³ - ?-x-7
-x³ - ?x-7 is not even , so it must be neither then? right?

 

[romanianxromo]

So it is still not even though, so it would be neither?


And for f(x) = x^2/?x^2 + 1

I got

f(-x)= (-x)^2 divided by ?(-x)^2 + 1 and got x^2 divided by ?x^2 + 1