function has tangent parallel to 4x-y-2=0 at (0,-2), f"(x)=12x^2-6x+4. Find fcn eqn.

[KeepItComing]

function has tangent parallel to 4x-y-2=0 at (0,-2), f"(x)=12x^2-6x+4. Find fcn eqn.

17. A function has a tangent parallel to the line 4x - y - 2 = 0 at the point (0, -2) and f"(x) = 12x² - 6x + 4. Find the equation of the function.

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Help me with a problem please folks ?

 

[stapel]

17. A function has a tangent parallel to the line 4x - y - 2 = 0 at the point (0, -2) and f"(x) = 12x² - 6x + 4. Find the equation of the function.

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Help me with a problem please folks ?

Please reply showing your work and thoughts so far, so we can see where you're getting stuck. For instance, you used the tangent information to find the slope at the given point. What value did you get? You integrated once to find the first derivative (plus a constant). How did you apply the slope to this information? And so forth.

Please be complete. Thank you!