function e5q8 *

tamiatha

Junior Member
Joined
Apr 26, 2009
Messages
109
if f(x) = 5x^2-4/x, find f(4)

my solution:
5(4)^2-4/4
20^2/4
400-4/4
99

AM I CORRECT :wink:
 
How did you get that 400 - 1 equalled 99? Or did you mean the function to be (5x^2 - 4)/x, rather than 5x^2 - (4/x)...?
 
Re: function: if f(x) = 5x^2-4/x, find f(4) (my answer: 99)

I GOT 400 BY 20^2 = 400

okkkkkkkkkkkkk
please look again
i copied the problem incorrectly onto the computer
now does my solution make sense
thanks for your help :oops:
 
Re: function: if f(x) = 5x^2-4/x, find 4 (my answer: 99)

tamiatha said:
if f(x) = 5x^2-4/x, find f(4)

my solution:
5(4)^2-4/4
20^2/4
400-4/4
99

AM I CORRECT :wink:

You need to clarify the problem for us. Which of these is the correct problem?

f(x) = (5x[sup:1th84bix]2[/sup:1th84bix] - 4) / x

OR

f(x) = 5x[sup:1th84bix]2[/sup:1th84bix] - (4/x)

It DOES make a difference!!

That said, the value of 5x[sup:1th84bix]2[/sup:1th84bix] when x = 4 is 5(4)[sup:1th84bix]2[/sup:1th84bix].....and that is NOT 400. You need to follow the order of operations. In evaluating 5(4)[sup:1th84bix]2[/sup:1th84bix], you must do the exponent FIRST, and then the multiplication.
 
Re: function e5q8

the problem is this
exactly;
if f(x) = 5x^2-4 / x, find f(4)
 
Re: function e5q8

tamiatha said:
the problem is this
exactly;
if f(x) = 5x^2-4 / x, find f(4)

If your problem look like:

\(\displaystyle f(x) \, = \, \frac{5x^2-4}{x}\)

in that case you should write it as:

f(x) = (5x^2 -4)/x

_________________________________

what you wrote -- f(x) = 5x^2-4 / x --- translates to (using PEMDAS):

\(\displaystyle f(x) \, = \, 5x^2 - \, \frac{4}{x}\)

Which one of the above correctly represent your problem?
 
Re: function e5q8 w

the first choice is what my problem is
not the second one
thank you
 
Re: function e5q8 w

(5(4)^2-4)/4 =
(5(16)-4)/4 =
(80-4)/4 =
76/4 =
19
 
Re: function e5q8 w

Tamiatha,

Aladdin has provided you with correct solution.

However, I strongly suggest that you understand - how is that different from the solution that you had provided and why was your solution incorrect. You did not follow principle of PEMDAS. That was also your trouble while posting - you did not use proper grouping symbols (brackets) - to indicate proper order of operations. You thought you posted the problem correctly - but in fact you had posted different problem, than you had meant to post.

You need to really get totally familiar with these routine operations - otherwise it will be very difficult as you try to proceed. the website "purplemath" gives you lot of worked out examples. Go through "every" problem and be confident that you can do those. These routine problems are very important - need to have those down-pat.

Good luck....
 
i will do as you advised because it IS very important-
thanks to you and aladdin for help and patience :D
 
Top