function composition and inverse.

mrcl

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May 31, 2013
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[FONT=MathJax_Math]Please help me solve this :
f(x)
[/FONT]
[FONT=MathJax_Main]=[/FONT][FONT=MathJax_Math]x[/FONT][FONT=MathJax_Main]2[/FONT][FONT=MathJax_Main]- 10x + 6
[/FONT]
[FONT=MathJax_Main]
the question is: find the (fo f -1)(x).[/FONT]
 
Last edited:
[FONT=MathJax_Math]Please help me solve this :
f(x)
[/FONT]
[FONT=MathJax_Main]=[/FONT][FONT=MathJax_Math]x[/FONT][FONT=MathJax_Main]2[/FONT][FONT=MathJax_Main]- 10x + 6
[/FONT]
[FONT=MathJax_Main]
the question is: find the (fo f -1)(x).[/FONT]
\(\displaystyle f(x) = x^2 - 10x + 6 \ \ \) has no inverse, because it is not a one-to-one function. No parabolas are one-to-one. Therefore, all parabolas have no inverses.
 
Just like sin(x) or cos(x) has corresponding inverse functions - with restricted domain and range - parabolas and other non-monotonic functions have corresponding inverse functions with restricted domain and ranges.
 
Since the graph of this is a parabola, with one increasing and one decreasing (and so one-to-one) piece, you could separate it into to functions at the vertex, giving an inverse function for each. That is NOT the same as " (fo f -1)(x)" but is the best you can do.
 
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