Fulcrum

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Psychguy98

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Dec 17, 2010
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A 60 lb weight is located 3 feet from the fulcrum of a lever. How much weight will balance the lever if located 4 feet from the fulcrum?


Do i need a specific formula?
 
Psychguy98 said:
A 60 lb weight is located 3 feet from the fulcrum of a lever. How much weight will balance the lever if located 4 feet from the fulcrum?


Do i need a specific formula? << Yes - Moment-balance equation <<< running out of red
Click to expand...
 
weight = w distance = d

and the 1 and 2's are smaller than the 'w' and 'd' I'm not sure how to format that.
 
Good nuff; don't forget they're just variables (like W1 is a variable); your problem:
"A 60 lb weight is located 3 feet from the fulcrum of a lever.
How much weight will balance the lever if located 4 feet from the fulcrum?"

W1 = 60, D1 = 3, W2 = ?, D2 = 4
W1 * D1 = W2 * D2
60 * 3 = W2 * 4
Solve that for W2...go ahead: we're waiting with baited breath :wink:
 
Psychguy98 said:
60 *3 = w2 * d2
180= w2 *4
square root 180 and 4w2
45 lbs = w2
Click to expand...
WHY "square root"?
4W2 = 180
W2 = 180 / 4
W2 = 45

I already told you: W2 is a simple variable: it's NOT W^2; you could use k instead of W2:
180 = k * 4
Get it?
 
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