frequency of oscillation

staceyrho

Junior Member
Joined
Jan 12, 2007
Messages
76
I have this problem, and I'm confused by the formula in it, so I'm not sure how to solve.

A wave on a string is described by the wave function
y= (0.1m) sin [0.5 rad/m) x- (20 rad/s) t]

determine the frequency of oscillation of a particular point at x= 2.0m. Answer in units of Hz.
 
\(\displaystyle \L f = \frac{\omega}{2\pi}\)

now ... what number represents \(\displaystyle \L \omega\) in the given linear wave equation?

y= (0.1m) sin [(0.5 rad/m) x- (20 rad/s) t]
 
it would be the 20 rad/s correct?

so I would tak (20 rad/s)/ (2(3.14)= .98 rad/s or am I way off here?
 
way off ... how can 20 divided by a number that is close to 6 possibly be .98 ?

(20 rad/s)/(2pi rad) is approx 3.2 Hz.

what kind of calculator do you own/operate?
 
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