Fractions

[myccbb]

Here is the problem I need help with: It has fractions so I decided I would type it and upload an image...

 

[Deleted member 4993]

Here is the problem I need help with: It has fractions so I decided I would type it and upload an image...

Can you evaluate the following - without using calculator?

\(\displaystyle \frac{1}{26-2} + \frac{3}{26-1}\)

 

[myccbb]

Here is the problem I need help with: It has fractions so I decided I would type it and upload an image...

Can you evaluate the following - without using calculator?

\(\displaystyle \frac{1}{26-2} + \frac{3}{26-1}\)

Yes...you just subtract in the denomintors right?

\(\displaystyle \frac{1}{24} + \frac{3}{25}\)
Then it would be 4 over something right? : \(\displaystyle \frac{4}{?}\)

Then find a common denominator...

Is that right??

 

[Deleted member 4993]

Here is the problem I need help with: It has fractions so I decided I would type it and upload an image...

Can you evaluate the following - without using calculator?

\(\displaystyle \frac{1}{26-2} + \frac{3}{26-1}\)

Yes...you just subtract in the denomintors right?

\(\displaystyle \frac{1}{24} + \frac{3}{25}\)
Then it would be 4 over something right? : \(\displaystyle \frac{4}{?}\) <<<< No - Please review your fraction manipulation before you do these problems
Then find a common denominator...

Is that right??

\(\displaystyle \frac{1}{24} + \frac{3}{25} = \frac{1\cdot 25}{24\cdot 25} + \frac{3 \cdot 24}{25\cdot 24} = \frac{25}{600} + \frac{72}{600} = \frac{97}{600}\)

You'll need to follow the same principle...

 

[Mrspi]

Here is the problem I need help with: It has fractions so I decided I would type it and upload an image...

Can you evaluate the following - without using calculator?

\(\displaystyle \frac{1}{26-2} + \frac{3}{26-1}\)

Yes...you just subtract in the denomintors right?

\(\displaystyle \frac{1}{24} + \frac{3}{25}\)
Then it would be 4 over something right? : \(\displaystyle \frac{4}{?}\)

Then find a common denominator...

Is that right??

Seems to me that you need to review some principles of arithmetic.

How would you find

(3/4) - (1/8)?

You wouldn't just subtract the numerators, would you?

No...you would write each fraction as an equivalent fraction so that you get the same denominator on BOTH.

The least common denominator for fourths and eighths is 8...

Write 3/4 as a fractions with 8 as its denominator: 3(2)/4(2) = 6/8
Write 1/8 as a fraction with 8 as its denominator. Oh wait, it already is!!!


(3/4) - (1/8) = (6/8) - (1/8) = (6 - 1)/ 8, or 5/8

Now..you need to do the same sort of thing on your problem.