fractions with exponents

[cr8zy4jj]

1)

m^2-7m/m-5 + 10/m-5


2)

Simplify only
y^2-5y-24 / y^2-3y-40 *fraction*

3) Find the reciprocal

4y^2 + 5 y

 

[stapel]

1) You have two fractions sharing a common denominator. Assuming you are supposed to simplify, where are you stuck?

2) Where are you stuck? You've factored the two quadratics and cancelled any common factors. What then? What is your question?

3) You've looked up the term "reciprocal" to refresh your memory, and... then what? Where are you stuck?

Please be complete. Thank you! :wink:

 

[fasteddie65]

1)

(m^2 - 7m)/(m - 5) + 10/(m - 5) = (m^2 - 7m + 10)/(m - 5) = (m - 5)(m - 2)/(m - 5) = m - 2
as long as m ? 5


2)

Simplify only
(y^2 - 5y - 2)/(y^2 - 3y - 40) *fraction*

The numerator is not factorable, but the denominator can be factored as (y - 8)(y + 5).


3) Find the reciprocal

4y^2 + 5y

4y^2 + 5y = y(4y + 5)
Its reciprocal is 1/[y(4y + 5)]