fractions w/ variables: (3/x+3)+1=7/x+3

Re: fractions w/ variables?

Show us what you've done and we'll help you out.

Hint: What can you multiply to both sides to get rid of the denominators of each fraction?
 
Re: fractions w/ variables?

is that \(\displaystyle \frac{3}{x+3}+1 = \frac{7}{x+3}\)

or...

\(\displaystyle (\frac{3}{x} + 3) + 1 = \frac{7}{x} + 3\)

Either way, when you have a rational and a constant, as is presented in both situations, you create a rational over a single common denominator:

example: \(\displaystyle \frac{x}{a} + b = \frac{x + ba}{a}\)

When you have created one rational on either side, cross multiply and start solving for your variable x
 
Re: fractions w/ variables?

(x+3)3/(x+3)+1(x+3)=(x+3)7/(x+3)

3+1(x+3)=7
3+x+3=7
x+6=7
x=1

???? is this right
 
Re: fractions w/ variables?

Yep, good job :wink:

You can always check your answer by plugging x back in to both sides to see if they are both equal. In this case, you'll get 1.75 = 1.75 which is true. So x = 1 is your solution.
 
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