Fractions in the exponents

K

Kim

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Aug 31, 2005
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problem: x to the 2/3 + 7x to the 1/3 - 8 = 0
do i let y=x to the 1/3?
 
Do you recall how to solve quadratic equations by factoring?

This equation is similar. It factors into

(x^1/3 - 8)(x^1/3 + 1) = 0 Note: easier to view if you write it out.

Can you get it from here. Rember, x^1/3 is the cube root of x.

Dave
 
so i got x=2, but what about the x^1/3=-1? is this where i'm suppose to use the "i" for a negative number, or is the answer just 2?
 
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