1 1 ------- + ------- 3 + c 3 - c where do I begin?
F flew62999 New member Joined Aug 30, 2005 Messages 47 Sep 21, 2005 #1 1 1 ------- + ------- 3 + c 3 - c where do I begin?
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Sep 21, 2005 #2 I will guess that you mean the following: . . . . .1/(3 + c) + 1/(3 - c) But what are you supposed to be doing with this? Eliz.
I will guess that you mean the following: . . . . .1/(3 + c) + 1/(3 - c) But what are you supposed to be doing with this? Eliz.
F flew62999 New member Joined Aug 30, 2005 Messages 47 Sep 21, 2005 #3 add them. so would i multiply each by -1 to change the denominator to c + 3 and c - 3
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Sep 21, 2005 #4 flew62999 said: 1 1 ------- + ------- 3 + c 3 - c where do I begin? Click to expand... looks like 1 / (3 +c) + 1 / (3 - c) multiply by lcd, which is (3 + c)(3 - c): that's where you begin.
flew62999 said: 1 1 ------- + ------- 3 + c 3 - c where do I begin? Click to expand... looks like 1 / (3 +c) + 1 / (3 - c) multiply by lcd, which is (3 + c)(3 - c): that's where you begin.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Sep 21, 2005 #5 Multiplying each of them by -1/-1 would give you: . . . . .-1/(-c - 3) - 1/(c - 3) Is that what you want? Or might it be better to muliply only the second fraction by -1/-1? Either way, you will need to convert the fractions to a common denominator before combining them. Eliz.
Multiplying each of them by -1/-1 would give you: . . . . .-1/(-c - 3) - 1/(c - 3) Is that what you want? Or might it be better to muliply only the second fraction by -1/-1? Either way, you will need to convert the fractions to a common denominator before combining them. Eliz.