Fraction Help! Confusing word problem
- Thread starter curlyqnic
- Start date
Hello, curlyqnic!
Let \(\displaystyle T\) = total number of students in class.
Let \(\displaystyle F\) = number of female students.
We are told that:. \(\displaystyle \frac{3}{8}T\) is the number of females in college wear.
We are also told that:. \(\displaystyle \frac{7}{10}F \) is the number of females in college wear.
Hence: .\(\displaystyle \frac{7}{10}F \:=\:\frac{3}{8}T \quad\Rightarrow\quad \dfrac{F}{T} \:=\:\dfrac{\frac{3}{8}}{\frac{7}{10}} \:=\:\dfrac{15}{28}\)
Therefore, female comprise \(\displaystyle \dfrac{15}{28}\) of the class.
Let \(\displaystyle T\) = total number of students in class.
Let \(\displaystyle F\) = number of female students.
We are told that:. \(\displaystyle \frac{3}{8}T\) is the number of females in college wear.
We are also told that:. \(\displaystyle \frac{7}{10}F \) is the number of females in college wear.
Hence: .\(\displaystyle \frac{7}{10}F \:=\:\frac{3}{8}T \quad\Rightarrow\quad \dfrac{F}{T} \:=\:\dfrac{\frac{3}{8}}{\frac{7}{10}} \:=\:\dfrac{15}{28}\)
Therefore, female comprise \(\displaystyle \dfrac{15}{28}\) of the class.
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- Apr 12, 2005
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You must be able to draw a 2x2 grid.
Hence: .\(\displaystyle \frac{7}{10}F \:=\:\frac{3}{8}T \quad\Rightarrow\quad \dfrac{F}{T} \:=\:\dfrac{\frac{3}{8}}{\frac{7}{10}} \:=\:\dfrac{15}{28}\)
shouldn't this be switched around? if 7/10 F over 3/8 T equals F/T, shouldn't 7/10 be on top of 3/8?
i need serious help with math
This is how I solved it, finding common numerators
7/10*3 21/30 21 represents females in class with college wear on and 30 represents total females in class
3/8*7 21/56 21 represents females dressed in college wear and 56 represents total students in the class.
So the answer is 30/56 30(total females in the class)/56(total students in the class)
does this make sense to anyone?